The first number is x. The third number is 3x. The second number is 3x-8.
x+3x+3x-8 = 112
7x=120 → x=120/7
The three numbers are 120/7, 304/7, 360/7. Or easier to visualize, 17 1/7, 43 3/7, 51 3/7.
I admittedly cheated because some quick attempts at an answer didn’t point me in the right direction. So I did this:
You’re welcome - I’m doing your homework problem for you.
Substitute x=0 into it. y =3. Substitute y=0 into it. x=2. You are now presented with a right triangle of height 3 and base 2 with the right...
An isosceles triangle does not have a hypotenuse. Only right triangles do.
70+ x + (x-20) = 180.
2x-20 = 110
So the triangle is 70, 65, and 45.
I’m glad I solved your homework assignment :)
They are inverse functions of each other. Rather than explain that, this should say it better than I could:
“The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides.”
n(n-3)/2=54 => n=12.
The polygon has twelve sides.
Ignore the 1/x portion. The question simply asks what the range of cos(y) is when you think about it, where I’m substituting y=1/x. You can map x to every value of its reciprocal, save for the case...
I did it both by hand (square the expression three times and then multiply by the original) and checked it on Wolfram Alpha. My answer matched. The answer is 378.
I originally said ten cuts, but thought of something.
If it’s paper, you could fold it in thirds one way, and cut down the long center of the folded paper. You now have two strips containing six box...
3, 13, 17
p has to be odd as the only even prime is 2, producing 12 and 16, neither of which is prime.
Any of the other odd numbers is either itself a multiple of three or either p+10 or p+14 will ...
2 points → 1 vertex
3 points (a triangle) → 3 vertices
4 points (quadrilateral) → 6 vertices (4 edges + 2 diagonals)
This ends up being the sequence of Pascal’s triangle or also the sum of integers 1…...
Someone will have a more rigorous answer, but here’s how I looked at it. I was assuming that the base in each case was an integer. It would also have to be a positive integer because the cube is po...